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Program code:
#include<stdio.h>
#include<conio.h>
void main()
{
int
a,b,c,d,e,f,g;
clrscr();
printf(“\nEnter
the 2 values:”);
scanf(“%d
%d “,&a,&b);
c=a+b;
d=a-b;
e=
a*b;
f=a/b;
g=a%b;
printf(“\nThe
sum is %d”,c);
printf(“\nThe
difference is %d”, d);
printf(“\nThe
product is %d”,e);
printf(“\nThe
divided result is %d”,f);
printf(“\nThe
modulus is %d”,g);
getch();
}
OUT PUT:
Enter the
2 values: 3 3
The sum
is 6
The difference
is 0
The product
is 9
The divided
result is 1
The modulus
is 0
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
#define PI 3.14
void main()
{
float r, area;
clrscr();
printf(“\nEnter the radius: ”);
scanf(‘%f”,&r);
area=PI*r*r;
printf(“\nThe area of circle is %f”,area);
getch();
}
OUT PUT
:
Enter the radius: 2
The area of a circle is 12.56
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
clrscr();
printf(“\nEnter the
values for a,b,c:);
scanf(“%d %d %d”,&a,&b,&c);
if (a>b&&a>c)
printf(“ \nThe biggest
number is %d”,a);
else if(b>c)
printf(“\nThe biggest
number is %d”,b);
else
printf(“\nThe biggest
number is %d”,c);
getch();
}
OUTPUT:
Enter the values
for a,b,c:2 9 6
The biggest number
is 9
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
float
f,c;
clrscr();
printf(“\nEnter
the temperature in farenheit: ”);
scanf(“
%f”,&f);
c=(f-32)/1.8;
printf(“\nTemperature
in Celsius is %f”,c);
getch();
}
OUTPUT:
Enter the temperature
in farenheit: 212
Temperature in
Celsius is 100.000000
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float
a,b,c,s,area;
clrscr();
printf(“\nEnter
the values for a,b,c:”);
scanf(“%f%f%f”,&a,&b,&c);
s=(a+b+c)/2;
area=sqrt(s*(s-a)*(s-b)*(s-c);
printf(“\nThe
area of triangle is %f ”,area);
getch();
}
OUT PUT:
Enter the values
for a,b,c:10 10 10
The area of triangle
is 43.301270
PROGRAM CODE:
#include<stdio.h>
#include,conio.h>
void main()
{
int
x=-1;y=1,z,i,n;
clrscr();
printf(“\nEnter
the n values:”);
scanf(‘%d”,&n);
printf(“%d”,&n)
printf(“\nThe
fibbonacci series:”)
for(i=0;i<n;i++)
{
z=x+y;
x=y;
y=z;
printf(“\n%d”,z);
}
getch();
}
OUTPUT:
Enter the n values:10
The fibbonacci series:
0
1
1
2
3
5
8
13
21
34
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
long
int fact=1,n,i;
clrscr();
printf(“\nEnter
the number: ”);
scanf(“%d”,&n);
for(i=1;i<=n;i++)
{
fact*=i;
}
printf(“\nThe
factorial of the number is %d”,fact);
getch();
}
OUT PUT:
Enter the number: 5
The factorial of the number
is 120
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int
r,n,n1,sum=0;
clrscr();
printf(“\nEnter
the number:”);
scanf(“%d’,&n);
n1=n;
while(n>0)
{
r=n%10;
n=n/10;
sum=(r*r*r)+sum;
}
if(sum==n1)
{
printf(“\nThe number %d is armstrong”);
}
else
{
printf(“\nThe number %d is not armstrong”);
}
getch();
}
OUT PUT:
Enter the number:153
The number 153
is armstrong
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int
a[10][10],n,i,j,s;
clrscr();
printf(“\nEnter
the no of rows:”);.
scanf(“%d”,&n);
for(i=0;i<n;i++)
{
for(s=n;s>i;s--)
printf(“ “);
a[i][j]=1;
printf(“%d”,a]i][j]);
if(i>0)
{
for(j=1;j<i;j++)
a[i][j]=a[i-1][j-1]+a[i-1][j];
}
a[i][j]=1;
printf(‘%d”,a[i][j]);
}
printf(‘\n”);
getch();
}
OUT PUT:
Enter the no of rows:4
1
1
2
1
1
3
3
1
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int
a[5][5],b[5][5],c[5][5],i,j,m,n,p,q,k;
clrscr();
printf(“\nEnter
the order of I matrix:”);
scanf(‘%d
%d”,&m,&n);
printf(“\nEnter
the order of II matrix:”);
scanf(‘%d
%d “,&p,&q);
if(n==p)
{
printf(“\nEnter the values of I matrix:”);
for(i=0;i<m;i++)
for(j=0;j<n;j++)
scanf(“%d”,&a[i][j]);
printf(“\nEnter the values of II matrix:”);
for(i=0;i<p;i++)
for(j=0;j<q;j++)
scanf(‘%d”,&b[i][j]);
printf(“\nMatrix multiplication axb:\n”);
for(i=0;i<m;i++)
{
for(j=0;j<q;j++)
{
c[i][i]=0;
for(k=0;k<p;k++)
c[i][i]=c[i][j]+a[i][k]*b[k][i];
}
else
{
printf(“Matrix multiplication is invalid “);
printf(“\nMatrix multiplication axb:\n”);
}
for(i=0;i<m;i++)
for(j=0;j<q;j++)
printf(“%d\t’,c[i][i]);
}
printf(“\n”);
}
getch();
}
OUT PUT:
Enter the order of I
matrix:2 2
Enter the order of II
matrix:2 2
Enter the value of I
matrix:2 2 2 2
Enter the value of II
matrix:2 2 2 2
Matrix multiplication
axb:
- 8
8 8
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int pid[10],quantity[10],rate[10],price[10],i,n;
char
pname[10];
clrscr();
printf(“\nEnter
the number of items:”);
scanf(“%d”,&n);
for(i=1;i<=n;i++)
{
printf(“\n\nEnter the product id:”);
scanf(“%s”,&pid[i]);
printf(“\nEnter the product name:”);
scanf(“%s”,&pname[i]);
printf(“Enter the rate of product:”);
scanf(“%d”,&rate[i]);
printf(“\nEnter the quantity:”);
scanf(“%d”,&quantity[i]);
}
clrscr();
printf(“\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\tSALES
REPORT”);
printf(“\n\t\t*---------------------*------------------*-------------------*”);
printf(“\n\t\t\t\pid\t\t\t\tproductname\t\t\t\trate\t\t\t\tquantity\t\t\t\tprice”);
for(i=1;i<=n;i++)
{
price[i]=rate[i]*quantity[i]);
printf(“\n\t\t\t%d\t\t\t\t\t\t\t\t\t\t\t %s\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t\t%d\t\t\t
\t\t\t\t%d\t\t\t\t\t\t\t\t%d”,pid[i],&pname[i]rate[i],quantity[i],price[i]”);
}
getch();
}
OUT PUT:
Enter
the number of items:2
Enter
the product id:001
Enter
the product name:shirt
Enter
the rate of product:350
Enter
the quantity:3
Enter
the product id:002
Enter
the product name:pant
Enter the
rate of product:500
Enter
the quantity:3
OUTPUT IN CONSOLE SCREEN:
SALES REPORT
*---------------------*------------------*-------------------*
pid
productname rate quantity
price
001 shirt
350 3
1050
002 pant
500 3
1500
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int
i,n;
float
x,sum,t;
clrscr();
printf(“\nEnter
the values of x,n:”);
scanf(“%f%d”,&x,&n);
x=(x*3.14)/180;
t=x;
sum=t;
for(i=1;i<=n;i++)
{
t=(t*(-1)*x*x)/(2*i((2*i)+1));
sum=sum+t;
}
printf(“\nValue of sine series
is %f”,sum);
getch();
}
OUT PUT:
Enter the values of x,n:45
1
Value of sine series is 0.704377
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int
i,n;
float
x,sum,t;
clrscr();
printf(“\nEnter
the values of x,n:”);
scanf(“%f%d”,&x,&n);
x=(x*3.14)/180;
t=1;
sum=t;
for(i=1;i<=n;i++)
{
t=(t*(-1)*x*x)/(2*i((2*i)-1));
sum=sum+t;
}
printf(“\nValue of Cosine
series is %f”,sum);
getch();
}
OUT PUT:
Enter the values of x,n:34
1
Value of Cosine series is 0.824110
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
char
s1[20],s2[20],s3[20];
int x,l1,l2,l3,f;
clrscr();
printf(“\nEnter the two string constants :\n”);
scanf(“%s%s”,s1,s2);
x=strcmp(s1,s2);
if(x!=0)
{
printf(“\n The string are not equal:”);
strcat(s1,s2);
}
else
printf(“\nThe strings are equal”);
strcpy(s3,s1);
l1=strlen(s1);
l2=strlen(S2);
l3=strlen(s3);
printf(“\ns1=%s\tlength=%d\n”,s1,l1);
printf(“\ns2=s2\t length=%d\n”,s2,l2);
printf(“\ns3=%s\t length=%d\n”,s3,l3);
f=strrev(s1,s2);
printf(“\nThe reversed string is %s”,f);
getch();
}
OUT PUT:
Enter the two string constants:
siva
siva
The strings are equal
s1=siva length=4
s2=siva length=4
s3=siva length=4
The reversed string is avis
PROGRAM
CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
int i,m;
float deviation,variance,list[20];
float sd(),va();
clrscr();
printf(“Standard deviation\n”);
printf(“Enter the upper limit:”);
scanf(“%d”,&n);
printf(“Enter the %d elements:\n”,n);
for(i=0;i<n;i++)
scanf(“%f”,&list[i]);
for(i=0;i<m;i++)
printf(“%6.2f”,list[i]);
deviation=3d(list,n);
variance=va(list,n);
printf(“variance is %6.5f \n”,variance);
printf(“standard deviation is %6.5f:\n”,deviation);
getch();
}
float sd(x,m);
float x[20];
int m;
{
int
i;
float
mean,div,sum=0.0;
float
avg();
mean=avg(x,m);
printf(“\nMean
of %2d elements is %5.2f\n”,mean);
for(i=1;i<=m;i++)
sum=sum+(mean-x[i])*(mean-x[i]);
div=sqrt+(sum/m);
return(div);
}
float va(x,m);
float x[20];
int m;
{
int
i;
float
mean,var,sum=0.0;
float
avg();
mean=avg(x,m);
for(i=0;i<=m;i++)
sum=sum+(mean-x[i])*(mean-x[i]);
var=sum/m;
return(var);
}
float avg(a,n)
float a[20]
{
int
i;
float
sum=0.0;
for(i=0;i<=n;i++)
sum+=a[i];
return(sum/n);
}
OUTPUT:
Standard deviation
Enter the upper limit:4
Enter the 4 elements:
1
3
4
5
Mean of 4 elements is 3.250000
Variance is 0.765620
standard deviation is -32766.0
PROGRAMCODE:
#include<stdio.h>
#include<conio.h>
int q=0
void main()
{
int
seq(int[],int,int);
int
i,n,x,b,q,z;
int
a[10];
clrscr();
printf(“\nEnter
the number of terms:”);
scanf(“%d”,&n);
printf(“\nEnter
the number”);
for(i=1;i<=n;i++)
{
scanf(“%d”,&a[i]);
}
printf(“\nEnter
the number to be found:”);
scanf(“%d”,&x);
b=seq(a,x,n);
if(b==q)
printf(“\n
the number is found at position %d”,q);
else
printf(“\n
the number is not found”)
getch();
}
int seq(int x[],int y,int z)
{
for(q=1;q<=z;q++)
{
if(x[q]==y)
{
return(q);
}
}
getch();
}
OUT PUT:
Enter the number of items 5
Enter the numbers 1 3
5 7 9
Enter the number to be found
5
The number is found at 3rd
position
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
struct stud
{
int roll_ no,m1,m2,m3,total;
char name[20];
float avg;
}s[10];
void main()
{
int
i,n;
clrscr();
printf(“\nstudents marksheet \n”);
printf(“\nEnter
the number of students:”);
scanf(“%d”,&n);
printf(“\n Enter the roll
no ,name and 3 subject marks:”);
for(i=1;i<=n;i++)
{
scanf(“%d%s%d%d%d”,&s[i].roll_no,&s[i].name,
&s[i].m1,&s[i].m2,&s[i].m3);
s[i].total=(s[i].m1+s[i].m2+s[i].m3);
s[i].avg=s[i]/3;
}
printf(“\n students marksheet ”);
printf(“\n\ROLLNO\tNAME\tMARK1\tMARK2\tMARK3\tTOTAL
\tAVERAGE\n”);
for(i=1;i<=n;i++)
{
printf(“%d\t%s\t%d\t%d\t%d\t%2f\n”,s[i].roll_no,
s[i].name,s[i].m1,s[i].m2,s[i].m3,s[i].total,s[i].avg);
}
getch();
}
OUTPUT
students marksheet
Enter the number of students:2
Enter the roll no ,name and
3 subject marks:
1 Abdul 99 95 95
Enter the datas
2 Arun 95 90
90
students marksheet
ROLLNO NAME
M1 M2 M3 TOTAL AVERAGE
1
Abdul 99 95
95
289 96.000000
2
Arun 95 90
90
275 91.000000
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
char
name[20];
int roll_no,m1[10],m2[10],m3[10],total[10],avg[10],n,i;
clrscr();
FILE *f1,*f2;
f1=fopen(“input.txt”,”w”);
printf(“\nEnter the number of students:”);
scanf(“%d”,&n);
for(i=0;i<=n;i++)
{
printf(“\nName:”);
scanf(“%s”,name[i]);
printf(“\nRoll no:”);
scanf(“%d”,&roll_no[i]);
printf(“\nMark1:”);
scanf(“%d”,&m1[i]);
printf(“\nMark2:);
scanf(“%d”,&m2[i]);
printf(“\nMark3:”);
scanf(“%d”,&m3[i]);
}
for(i=0;i<=n;i++)
{
fprintf(f1,”\nName:%s”,name[i]);
fprintf(f1,”\nRoll
no:%d”,roll_no[i]);
fprintf(f1,”\nm1:%d\nm2:%d\nm3:%d”,m1[i],m2[i],m3[i]);
fclose(f1);
f1=fopen(input.txt”,”r”);
f2=fopen(“Output.txt”,”w”);
for(i=0;i<.=n;i++)
{
fscanf(f1,”%d”,&m1[i]);
fscanf(f2,”%d”,&m2[i]);
fscanf(f3,”%d”,&m3[i]);
total=m1+m2[i]+m3[i];
avg=total/3;
printf(“\n Roll no\tName\ttotal\taverage\n”);
for(i=0;i<=n;i++)
{
printf(“%d\t\t\t\t\t\t\t\t%s\t\t\t\t\t%d\t\t\t\t\t%d\t\t\t\t\t%d\n”
,roll_no[i],name[i],total[i],avg);
}
fprintf(f2,”\nRoll no\t Name\tTotal\taverage\n”);
for(i=0;i<=n;i++)
fprintf(f2,”%d\t\t\t\t\\t\t%s\t\t\t\t\t\t%d\t\t\t\t\t%d”,
roll_no[i],name[i],total[i],avg[i]);
fclose(f1);
fclose(f2);
getch();
}
OUT PUT:
Enter the number of students:2
INPUT.TXT:
Name:Ashok
Roll no:1
Mark1:90
Mark2:80
Mark3:80
Enter the name:Bala
Roll no:2
Mark1:80
Mark2:80
Mark3:90
OUTPUT.TXT:
Rollno Name Total average
1
Ashok 250 85
2
Bala 250
85
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
char ch;
FILE *f1,*f2,*f3;
f1=fopen(“input1.txt”,”r”);
f2=fopen(“input2.txt”,”r”);
f3=fopen(“output.txt”,”w”);
printf(“\n First file data:”);
while(!feof(f1))
{
ch=fgetc(f1);
printf(“%c”,ch);
fputc(ch,f3);
}
printf(“\n Second file data:”);
while(!feof(f2)
{
ch=fgetc(f2);
printf(“%c”,ch);
fputc(ch,f3);
}
printf(“\n The two files merged successfully”);
fclose(f1);
fclose(f2);
fclose(f3);
getch();
}
OUT PUT:
INPUT1.TXT:
Sachin
INPUT2.TXT:
Tendulkar
OUTPUT IN CONSOLE SCREEN:
First file data: Sachin
Second file data: Tendulkar
Output file data:Sachin Tendulkar
PROGRAM CODE:
#include<stdio.h>
#include<conio.h>
void main()
{
char
str[20],temp[50];
int
i=0,j=0,n;
clrscr();
printf(“\nEnter
the number of persons:”);
scanf(“%d”,&n);
printf(“\nEnter the name of persons: ”);
for(i=0;i<n;i++)
{
scanf(“\n%s”,str[i]);
}
printf(“\nThe names in alphabetical
order:”);
for(i=1;i<n;i++)
{
if(strcmp(str[j-1],str[j]>0));
{
strcpy(temp,str[j-1]);
strcpy(str[j-1],str[j]);
strcpy(str[j],temp);
}
}
}
for(i=0;i<n;i++)
{
printf(“\n%s”,str[i]);
}
getch();
}
OUT PUT:
Enter the number of persons:4
Enter the name of persons:
Siva
Raja
Vel
Arun
The names in alphabetical order:
Arun
Raja
Siva
Vel
YOUNGBLOOD